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  4. C 6 H 5 ⋅ CH 3 xrightarrow[H2SO4] K 2 Cr 2 O 7Y, Here Y is:

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Q. $C _{6} H _{5} \cdot CH _{3} \xrightarrow[H_2SO_4]{ K _{2} Cr _{2} O _{7}}Y$, Here $Y$ is:

JIPMERJIPMER 2002

Solution:

Toluene, gives different oxidation products, with different oxidizing agents. With $CrO _{2} Cl _{2}$, it gives benzaldehyde, while with $KMnO _{4} / H ^{+}$or $K _{2} Cr _{2} O _{7} / H ^{+}$, it gives benzoic acid.

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