Boron has two stable isotopes, 10B(19%) and 11B(81%).The atomic mass that should appear for boron in the periodic table is

Question

Boron has two stable isotopes, 10B(19%) and 11B(81%).The atomic mass that should appear for boron in the periodic table is (A) 10.8 (B) 10.2 (C) 11.2 (D) 10.0

Tardigrade Admin · Accepted Answer

Atomic mass =(10×19+81×11/100) =(190+891/100) =(1081/100)=10.81

Q. Boron has two stable isotopes, $^{10} B$ (19%) and $^{11} B$ (81%).The atomic mass that should appear for boron in the periodic table is

$10.8$

$10.2$

$11.2$

$10.0$

Atomic mass $= \frac{10 \times 19 + 81 \times 11}{100}$
$= \frac{190 + 891}{100}$
$= \frac{1081}{100} = 10.81$

Q. Boron has two stable isotopes, 10B(19%) and 11B(81%).The atomic mass that should appear for boron in the periodic table is

10.8

10.2

11.2

10.0