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Q. Boron has two stable isotopes, $^{10}B$(19%) and $^{11}B$(81%).The atomic mass that should appear for boron in the periodic table is

Some Basic Concepts of Chemistry

Solution:

Atomic mass $=\frac{10\times19+81\times11}{100}$
$=\frac{190+891}{100}$
$=\frac{1081}{100}=10.81$