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Chemistry
Boron has two stable isotopes, 10B(19%) and 11B(81%).The atomic mass that should appear for boron in the periodic table is
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Q. Boron has two stable isotopes, $^{10}B$(19%) and $^{11}B$(81%).The atomic mass that should appear for boron in the periodic table is
Some Basic Concepts of Chemistry
A
$10.8$
59%
B
$10.2$
11%
C
$11.2$
16%
D
$10.0$
14%
Solution:
Atomic mass $=\frac{10\times19+81\times11}{100}$
$=\frac{190+891}{100}$
$=\frac{1081}{100}=10.81$