Bond order of Cl - O bond in ClO 4-is

Question

Bond order of Cl - O bond in ClO 4-is (A) 2 (B) 1.5 (C) 1.33 (D) 1.75

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/5c32621916b3b9b48b1dd4979051fe4f-.png" /> Bond order ( Cl - O ) =( text Total no. of bonds (σ+π)/ text Total no. of σ text -bond ) =(7/4)=1.75

Q. Bond order of $Cl - O$ bond in $Cl O_{4}^{-}$ is

2

1.5

1.33

1.75

Bond order $(Cl - O) = \frac{Total no. of bonds ( σ + π )}{Total no. of σ -bond}$
$= \frac{7}{4} = 1.75$

Q. Bond order of Cl−O bond in ClO4−​is

2

1.5

1.33

1.75

Bond order (Cl−O)= Total no. of σ-bond Total no. of bonds (σ+π)​ =47​=1.75

Q. Bond order of $Cl - O$ bond in $Cl O_{4}^{-}$ is

Bond order $(Cl - O) = \frac{Total no. of bonds ( σ + π )}{Total no. of σ -bond}$
$= \frac{7}{4} = 1.75$