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  4. Bond order of Cl - O bond in ClO 4-is

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Q. Bond order of $Cl - O$ bond in $ClO _{4}^{-}$is

Solution:

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Bond order $( Cl - O ) =\frac{\text { Total no. of bonds }(\sigma+\pi)}{\text { Total no. of } \sigma \text {-bond }}$
$=\frac{7}{4}=1.75$