Bond dissociation on energy of Cl2 is 240 k J / m o l . The longest wavelength of photon that can break this bond would be [NA = 6 × 1023 , h = 6.6 × 10- 34 J / s]

Question

Bond dissociation on energy of Cl2 is 240 k J / m o l . The longest wavelength of photon that can break this bond would be [NA = 6 × 1023 , h = 6.6 × 10- 34 J / s] (A) 4.95× 10- 7m (B) 9.9× 10- 7m (C) 4.95× 10- 6m (D) 9.9× 10- 6m

Tardigrade Admin · Accepted Answer

E=NA× (h C/λ ) 240× 103=(6 × 1023 × 6 ⋅ 6 × 10- 34 × 3 × 108/λ ) λ =4.95× 10- 7 m

Q. Bond dissociation on energy of $C l_{2}$ is $240 k J / m o l$ . The longest wavelength of photon that can break this bond would be $[N_{A} = 6 \times 1 0^{23}, h = 6.6 \times 1 0^{- 34} J / s]$

$4.95 \times 1 0^{- 7} m$

$9.9 \times 1 0^{- 7} m$

$4.95 \times 1 0^{- 6} m$

$9.9 \times 1 0^{- 6} m$

$E = N_{A} \times \frac{h C}{λ}$

$240 \times 1 0^{3} = \frac{6 \times 1 0 ^{23} \times 6 \cdot 6 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{λ}$

$λ = 4.95 \times 1 0^{- 7} m$

Q. Bond dissociation on energy of Cl2​ is 240kJ/mol . The longest wavelength of photon that can break this bond would be [NA​=6×1023,h=6.6×10−34J/s]

4.95×10−7m

9.9×10−7m

4.95×10−6m

9.9×10−6m