Boiling point of CHCl 3 was raised by 0.29 K when 0.5 g anthracene was dissolved in 35 g CHCl 3 . Molecular mass of anthracene is 178 u. The boiling point elevation constant ( K b ) of CHCl 3 is K kg mol -1.

Question

Boiling point of CHCl 3 was raised by 0.29 K when 0.5 g anthracene was dissolved in 35 g CHCl 3 . Molecular mass of anthracene is 178 u. The boiling point elevation constant ( K b ) of CHCl 3 is K kg mol -1. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

K b =(Δ T b / text molality ); ∴ K b =(Δ T b × M B × W A / W B ) ∴ =(0.29 × 178 × 35 × 10-3/0.5) =3.61 K kg mol -1

Q. Boiling point of $C H C l_{3}$ was raised by $0.29 K$ when $0.5 g$ anthracene was dissolved in $35 g$ $C H C l_{3} .$ Molecular mass of anthracene is $178 u$ . The boiling point elevation constant $(K_{b})$ of $C H C l_{3}$ is_______ $K k g m o l^{- 1}$ .

$K_{b} = \frac{Δ T _{b}}{molality}$ ;
$∴ K_{b} = \frac{Δ T _{b} \times M _{B} \times W _{A}}{W _{B}}$
$∴ = \frac{0.29 \times 178 \times 35 \times 1 0 ^{- 3}}{0.5}$
$= 3.61 K k g m o l^{- 1}$

Q. Boiling point of CHCl3​ was raised by 0.29K when 0.5g anthracene was dissolved in 35g CHCl3​. Molecular mass of anthracene is 178u. The boiling point elevation constant (Kb​) of CHCl3​ is_______ Kkgmol−1.

Kb​= molality ΔTb​​; ∴Kb​=WB​ΔTb​×MB​×WA​​ ∴=0.50.29×178×35×10−3​ =3.61Kkgmol−1

Q. Boiling point of $C H C l_{3}$ was raised by $0.29 K$ when $0.5 g$ anthracene was dissolved in $35 g$ $C H C l_{3} .$ Molecular mass of anthracene is $178 u$ . The boiling point elevation constant $(K_{b})$ of $C H C l_{3}$ is_______ $K k g m o l^{- 1}$ .

$K_{b} = \frac{Δ T _{b}}{molality}$ ;
$∴ K_{b} = \frac{Δ T _{b} \times M _{B} \times W _{A}}{W _{B}}$
$∴ = \frac{0.29 \times 178 \times 35 \times 1 0 ^{- 3}}{0.5}$
$= 3.61 K k g m o l^{- 1}$