1. Tardigrade
  2. Question
  3. Chemistry
  4. Boiling point of CHCl 3 was raised by 0.29 K when 0.5 g anthracene was dissolved in 35 g CHCl 3 . Molecular mass of anthracene is 178 u. The boiling point elevation constant ( K b ) of CHCl 3 is K kg mol -1.

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Q. Boiling point of $CHCl _{3}$ was raised by $0.29\, K$ when $0.5 \,g$ anthracene was dissolved in $35\, g$ $CHCl _{3} .$ Molecular mass of anthracene is $178\, u$. The boiling point elevation constant $\left( K _{ b }\right)$ of $CHCl _{3}$ is_______ $K\, kg\, mol ^{-1}$.

Solutions

Solution:

$K _{ b }=\frac{\Delta T _{ b }}{\text { molality }}$;
$\therefore K _{ b } =\frac{\Delta T _{ b } \times M _{ B } \times W _{ A }}{ W _{ B }}$
$\therefore =\frac{0.29 \times 178 \times 35 \times 10^{-3}}{0.5}$
$=3.61\, K\, kg\, mol ^{-1}$