Beats are produced by two waves given by y 1= a sin 2000 π t and y 2= a sin 2008 π t . The number of beats heard per second

Question

Beats are produced by two waves given by y 1= a sin 2000 π t and y 2= a sin 2008 π t . The number of beats heard per second (A) Zero (B) One (C) Four (D) Eight

Tardigrade Admin · Accepted Answer

General equation of waves y0=a sin ω t ω1=2000 π ω2=2008 π 2 π f1=2000 π 2 π f2=2008 π f1=1000 Hz f 2=1004 Hz beats = f 2- f 1 =1004-1000 =4 Hz

Q. Beats are produced by two waves given by $y_{1} = a sin$ $2000 π t$ and $y_{2} = a sin 2008 π t .$ The number of beats heard per second

Zero

One

Four

Eight

General equation of waves
$y_{0} = a sin ω t$
$ω_{1} = 2000 π ω_{2} = 2008 π$
$2 π f_{1} = 2000 π 2 π f_{2} = 2008 π$
$f_{1} = 1000 Hz f_{2} = 1004 Hz$
beats $= f_{2} - f_{1}$
$= 1004 - 1000$
$= 4 Hz$

Q. Beats are produced by two waves given by y1​=asin 2000πt and y2​=asin2008πt. The number of beats heard per second

Zero

One

Four

Eight

General equation of waves y0​=asinωt ω1​=2000πω2​=2008π 2πf1​=2000π2πf2​=2008π f1​=1000Hzf2​=1004Hz beats =f2​−f1​ =1004−1000 =4Hz

Q. Beats are produced by two waves given by $y_{1} = a sin$ $2000 π t$ and $y_{2} = a sin 2008 π t .$ The number of beats heard per second

General equation of waves
$y_{0} = a sin ω t$
$ω_{1} = 2000 π ω_{2} = 2008 π$
$2 π f_{1} = 2000 π 2 π f_{2} = 2008 π$
$f_{1} = 1000 Hz f_{2} = 1004 Hz$
beats $= f_{2} - f_{1}$
$= 1004 - 1000$
$= 4 Hz$