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Q. Beats are produced by two waves given by $y _{1}= a \sin$ $2000 \pi t$ and $y _{2}= a \sin 2008 \pi t .$ The number of beats heard per second

Waves

Solution:

General equation of waves
$y_{0}=a \sin \omega t$
$\omega_{1}=2000 \pi\,\, \omega_{2}=2008 \pi$
$2 \pi f_{1}=2000 \pi \,\,2 \pi f_{2}=2008 \pi$
$f_{1}=1000 Hz\, f _{2}=1004 Hz$
beats $= f _{2}- f _{1}$
$=1004-1000$
$=4\, Hz$