Be2C + 4 H2O arrow 2 X + CH4 X + 2 HCl arrow Y 'X' and 'Y' formed in the above two reactions are -

Question

Be2C + 4 H2O arrow 2 X + CH4 X + 2 HCl arrow Y 'X' and 'Y' formed in the above two reactions are - (A) BeCO3 and Be(OH)2 ; respectively (B) Be(OH)2 and BeCl2 ; respectively (C) Be(OH)2 and [Be(OH)4]Cl2 ; respectively (D) [Be(OH)4]2- and BeCl2 ; respectively

Tardigrade Admin · Accepted Answer

Be2C + 4H2O → 2 Be(OH)2 + CH4 Thus, 'X' is Be(OH)2. Next, X reacts with HCl to form: Be(OH)2 + 2HCl → BeCl2 + 2H2O Thus, 'Y' is BeCl2.

Q. Be₂C + 4 H₂O $\to$ 2 X + CH₄

X + 2 HCl $\to$ Y

'X' and 'Y' formed in the above two reactions are -

BeCO₃ and Be(OH)₂ ; respectively

Be(OH)₂ and BeCl₂ ; respectively

Be(OH)₂ and [Be(OH)₄]Cl₂ ; respectively

[Be(OH)₄]^2- and BeCl₂ ; respectively

Be₂C + 4H₂O → 2 Be(OH)₂ + CH₄

Thus, 'X' is Be(OH)₂.

Next, X reacts with HCl to form:

Be(OH)₂ + 2HCl → BeCl₂ + 2H₂O

Thus, 'Y' is BeCl₂.

Q. Be2C + 4 H2O → 2 X + CH4 X + 2 HCl → Y 'X' and 'Y' formed in the above two reactions are -

BeCO3 and Be(OH)2 ; respectively

Be(OH)2 and BeCl2 ; respectively

Be(OH)2 and [Be(OH)4]Cl2 ; respectively

[Be(OH)4]2- and BeCl2 ; respectively