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  4. Be2C + 4 H2O arrow 2 X + CH4 X + 2 HCl arrow Y 'X' and 'Y' formed in the above two reactions are -

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Q. Be2C + 4 H2O $ \rightarrow $ 2 X + CH4

X + 2 HCl $ \rightarrow $ Y

'X' and 'Y' formed in the above two reactions are -

NTA AbhyasNTA Abhyas 2020The s-Block Elements

Solution:

Be2C + 4H2O → 2 Be(OH)2 + CH4

Thus, 'X' is Be(OH)2.

Next, X reacts with HCl to form:

Be(OH)2 + 2HCl → BeCl2 + 2H2O

Thus, 'Y' is BeCl2.