Base strength of (i) H 3 C overset ominus C H 2 (ii) H 2 C = overset ominus CH (iii) H - C ≡ C ominus is in the order of

Question

Base strength of (i) H 3 C overset ominus C H 2 (ii) H 2 C = overset ominus CH (iii) H - C ≡ C ominus is in the order of (A) (ii) > (i) > (iii) (B) (iii) > (ii) > (i) (C) (i) > (iii) > (ii) (D) (i) > (ii) > (iii)

Tardigrade Admin · Accepted Answer

Weaker the acid, strongest is its conjugate base. Among alkane, alkene and alkyne, alkynes are most acidic and alkanes are least acidic, so the order of base strength is
alkane

>

alkene

>

alkyne or

C H_{3} C ⊖ H_{2} > H_{2} C = C ⊖ H > H - C \equiv C ⊖

Q. Base strength of (i) H3​CC⊖H2​ (ii) H2​C=C⊖H (iii) H−C≡C⊖ is in the order of

(ii) > (i) > (iii)

(iii) > (ii) > (i)

(i) > (iii) > (ii)

(i) > (ii) > (iii)

Weaker the acid, strongest is its conjugate base. Among alkane, alkene and alkyne, alkynes are most acidic and alkanes are least acidic, so the order of base strength is alkane > alkene > alkyne or CH3​C⊖H2​>H2​C=C⊖H>H−C≡C⊖

Q. Base strength of
(i) $H_{3} C C ⊖ H_{2}$
(ii) $H_{2} C = C ⊖ H$
(iii) $H - C \equiv C^{⊖}$
is in the order of

Weaker the acid, strongest is its conjugate base. Among alkane, alkene and alkyne, alkynes are most acidic and alkanes are least acidic, so the order of base strength is
alkane $>$ alkene $>$ alkyne or
$C H_{3} C ⊖ H_{2} > H_{2} C = C ⊖ H > H - C \equiv C ⊖$