Tardigrade
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Tardigrade
Question
Chemistry
B.P. of H2O (100°C) and H2S (-42°C) is explained by
Q.
B
.
P
. of
H
2
O
(
10
0
∘
C
)
and
H
2
S
(
−
4
2
∘
C
)
is explained by
1945
220
Chemical Bonding and Molecular Structure
Report Error
A
van der Waals forces
4%
B
Covalent bond
0%
C
Hydrogen bond
96%
D
Ionic bond
0%
Solution:
Boiling point of
H
2
O
is more than that of
H
2
S
because
H
2
O
forms hydrogen bonding while
H
2
S
does not.