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  4. B.P. of H2O (100°C) and H2S (-42°C) is explained by

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Q. $B.P$. of $H_2O (100^{\circ}C)$ and $H_2S (-42^{\circ}C)$ is explained by

Chemical Bonding and Molecular Structure

Solution:

Boiling point of $H_2O$ is more than that of $H_2S$ because $H_2O$ forms hydrogen bonding while $H_2S$ does not.