B1 g of an element gives B2 g of its chloride, the equivalent mass of the element is:

Question

B1 g of an element gives B2 g of its chloride, the equivalent mass of the element is: (A) (B1/B2-B1) × 35.5 (B) (B2/B2-B1) × 35.5 (C) (B2-B1/B1) × 35.5 (D) (B2-B1/B2) × 35.5

Tardigrade Admin · Accepted Answer

Mass of chloride =( B 2- B 1) g ( B 2- B 1) g combines with metal = B 1 g ∴ 35.5 g combines with metal =(35.5 × B 1 g / B 2- B 1)

Q. $B_{1} g$ of an element gives $B_{2} g$ of its chloride, the equivalent mass of the element is:

$\frac{B _{1}}{B _{2} - B _{1}} \times 35.5$

$\frac{B _{2}}{B _{2} - B _{1}} \times 35.5$

$\frac{B _{2} - B _{1}}{B _{1}} \times 35.5$

$\frac{B _{2} - B _{1}}{B _{2}} \times 35.5$

Mass of chloride $= (B_{2} - B_{1}) g$

$(B_{2} - B_{1}) g$ combines with metal $= B_{1} g$

$∴ 35.5 g$ combines with metal $= \frac{35.5 \times B _{1} g}{B _{2} - B _{1}}$

Q. B1​g of an element gives B2​g of its chloride, the equivalent mass of the element is:

B2​−B1​B1​​×35.5

B2​−B1​B2​​×35.5

B1​B2​−B1​​×35.5

B2​B2​−B1​​×35.5