Question

$B_{1}\, g$ of an element gives $B_{2}\, g$ of its chloride, the equivalent mass of the element is:

• A. $\frac{B_{1}}{B_{2}-B_{1}} \times 35.5$
• B. $\frac{B_{2}}{B_{2}-B_{1}} \times 35.5$
• C. $\frac{B_{2}-B_{1}}{B_{1}} \times 35.5$
• D. $\frac{B_{2}-B_{1}}{B_{2}} \times 35.5$

Answer 1

Answer: (A)

Mass of chloride $=\left( B _{2}- B _{1}\right) g$

$\left( B _{2}- B _{1}\right) g$ combines with metal $= B _{1} g$

$\therefore 35.5 \, g$ combines with metal $=\frac{35.5 \times B _{1} \, g }{ B _{2}- B _{1}}$