Avogadro’s number of oxygen atom weighs

Question

Avogadro’s number of oxygen atom weighs (A) 32 g (B) 8 g (C) 56 g (D) 16 g

Tardigrade Admin · Accepted Answer

Weight of 6.023 × 1023 molecules of oxygen ( O 2)=32 g . Since the oxygen is diatomic, therefore weight of Avogadro's number of oxygen atom =(32/2) =16 g

Q. Avogadro’s number of oxygen atom weighs

32 g

8 g

56 g

16 g

Weight of $6.023 \times 1 0^{23}$ molecules of oxygen $(O_{2}) = 32 g .$

Since the oxygen is diatomic, therefore weight of Avogadro's number of oxygen atom $= \frac{32}{2}$

$= 16 g$

Q. Avogadro’s number of oxygen atom weighs

32 g

8 g

56 g

16 g

Weight of 6.023×1023 molecules of oxygen (O2​)=32g. Since the oxygen is diatomic, therefore weight of Avogadro's number of oxygen atom =232​ =16g

Weight of $6.023 \times 1 0^{23}$ molecules of oxygen $(O_{2}) = 32 g .$

Since the oxygen is diatomic, therefore weight of Avogadro's number of oxygen atom $= \frac{32}{2}$

$= 16 g$