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Q. Avogadro’s number of oxygen atom weighs

AIIMSAIIMS 1996Some Basic Concepts of Chemistry

Solution:

Weight of $6.023 \times 10^{23}$ molecules of oxygen $\left( O _{2}\right)=32\, g .$

Since the oxygen is diatomic, therefore weight of Avogadro's number of oxygen atom $=\frac{32}{2}$

$=16 \,g$