Question

At what temperature volume of an ideal gas at $0{}^{\circ }C$ becomes triple?

• A. $546{}^{\circ }C$
• B. $182{}^{\circ }C$
• C. $819{}^{\circ }C$
• D. $646{}^{\circ }C$

Answer 1

Answer: (A)

We know that for ideal gas $\frac{V_1}{T_1}=\frac{V_2}{T_2}$.
(at constant pressure)
$\Rightarrow T_2=\frac{V_2}{V_1}\times T_1=\frac{3V}{V}\times 273$
$=3\times 273K$
$\Rightarrow T_2=819K=819-273$
$=546^{\circ }C$