Question

At what temperature volume of an ideal gas at $ 0{}^\circ C $ becomes triple?

• A. $ 546{}^\circ C $
• B. $ 182{}^\circ C $
• C. $ 819{}^\circ C $
• D. $ 646{}^\circ C $

Answer 1

Answer: (A)

We know that for ideal gas $\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$.
(at constant pressure)
$\Rightarrow T_{2} =\frac{V_{2}}{V_{1}} \times T_{1}=\frac{3 V}{V} \times 273 $
$=3 \times 273 \,K $
$\Rightarrow T_{2} =819 \,K =819-273 $
$=546^{\circ} C$