At the highest point of a projectile instantaneous power of gravity is [u is initial velocity and θ is angle of projection with horizontal]

Question

At the highest point of a projectile instantaneous power of gravity is [u is initial velocity and θ is angle of projection with horizontal] (A) mgucosθ (B) mgusinθ (C) mgu (D) Zero

Tardigrade Admin · Accepted Answer

At the highest point vecF ⊥ vecv so P = vecF ⋅ vecv = 0

Q. At the highest point of a projectile instantaneous power of gravity is [ $u$ is initial velocity and $θ$ is angle of projection with horizontal]

$m gu cos θ$

$m gu s in θ$

$m gu$

Zero

At the highest point $F ⊥ v$
so $P = F \cdot v = 0$

Q. At the highest point of a projectile instantaneous power of gravity is [u is initial velocity and θ is angle of projection with horizontal]

mgucosθ

mgusinθ

mgu