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  4. At the highest point of a projectile instantaneous power of gravity is [u is initial velocity and θ is angle of projection with horizontal]

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Q. At the highest point of a projectile instantaneous power of gravity is [$u$ is initial velocity and $\theta$ is angle of projection with horizontal]

Solution:

At the highest point $\vec{F} \bot\vec{v}$
so $P = \vec{F} \cdot \vec{v} = 0$