At STP, the density of CCl4 vapour in g/L will be nearest to

Question

At STP, the density of CCl4 vapour in g/L will be nearest to (A) 6.87 (B) 3.42 (C) 10.26 (D) 4.57

Tardigrade Admin · Accepted Answer

1 mole C C 14 vapours =12+4 × 35.5=154 g At STP, volume of 1 mole of a gas =22.4 L Thus, 154 g=22.4 L ∴ Density of C C l4 vapours =(154/22.4) g L-1 =6.87 g L-1

Q. At STP, the density of $CC l_{4}$ vapour in g/L will be nearest to

6.87

3.42

10.26

4.57

$1$ mole $CC 1_{4}$ vapours $= 12 + 4 \times 35.5 = 154 g$
At STP, volume of $1$ mole of a gas $= 22.4 L$
Thus, $154 g = 22.4 L$
$∴$ Density of $CC l_{4}$ vapours $= \frac{154}{22.4} g L^{- 1}$
$= 6.87 g L^{- 1}$

Q. At STP, the density of CCl4​ vapour in g/L will be nearest to