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Q.
At STP, the density of $CCl_4$ vapour in g/L will be nearest to
AIPMTAIPMT 1988Some Basic Concepts of Chemistry
Solution:
$1$ mole $C C 1_{4}$ vapours $=12+4 \times 35.5=154\, g$
At STP, volume of $1$ mole of a gas $=22.4 \,L$
Thus, $154 g=22.4 \,L$
$\therefore $ Density of $ C C l_{4}$ vapours $=\frac{154}{22.4} \,g\, L^{-1}$
$=6.87 \,g \,L^{-1}$