Question

At STP $1.12$ litre of $H_2$ is obtained on flowing a current for $965$ seconds in a solution. The valueof current is

• A. 10
• B. 1.0
• C. 1.5
• D. 2.0

Answer 1

Answer: (A)

$2H^{+}+\underset{\text{2 mole 2F 2}\times 96500C}{2e^{-}}\to \underset{\text{1 mole 22.4 lt}}{H_{2}O}$
To libarate $22.5lt$ of $H_2$ gas, electricity required
$=2\times 96500C$
To liberate $1.12lt$ of $H_2$ gas, electricity required
$=\frac{2\times 96500\times 1.12}{22.4}=9650C$
$Q=1t$
$1=\frac{Q}{t}$
$=\frac{9650C}{965\sec }$
$=10$ ampere