Question

At S.T.P. the volume of 7.5 g of a gas is 5.6L. The gas is

• A. NO
• B. $N_{2}O$
• C. CO
• D. $C{O}_2$

Answer 1

Answer: (A)

$\because$ 5.6L at S.T.P weighs 7.5g
$\therefore$22.4L at S.T.P weighs $\frac{7.5\times 22.4}{5.6}=30g$
Molar mass = 30g/mol (True for NO)