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Chemistry
At S.T.P. the volume of 7.5 g of a gas is 5.6L. The gas is
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Q. At S.T.P. the volume of 7.5 g of a gas is 5.6L. The gas is
WBJEE
WBJEE 2019
A
NO
B
$N_{2}O$
C
CO
D
$CO_{2}$
Solution:
$\because$ 5.6L at S.T.P weighs 7.5g
$\therefore $22.4L at S.T.P weighs $\frac{7.5\times22.4}{5.6} =30g$
Molar mass = 30g/mol (True for NO)