At NTP, 1 L of O2 reacts with 3 L of carbon monoxide. What will be the volume of CO and CO2 after the reaction?

Question

At NTP, 1 L of O2 reacts with 3 L of carbon monoxide. What will be the volume of CO and CO2 after the reaction? (A) 1 L CO2, 1 L CO (B) 2 L CO2, 2 L CO (C) 1 L CO2, 2 L CO (D) 2 L CO2, 1 L CO

Tardigrade Admin · Accepted Answer

underset text2 vol2CO+ underset text1 volO2 → underset text2 vol2CO2 1 vol of O2 reacts with 2 vol of CO 1 L of O2 reacts with 2 L of CO CO left after reaction = 3 - 2 = 1 L 1 L of O2 produces 2 L of CO2. Hence, after the reaction, CO = 1 L, CO2 = 2 L

Q. At $NTP$ , $1 L$ of $O_{2}$ reacts with $3 L$ of carbon monoxide. What will be the volume of $CO$ and $C O_{2}$ after the reaction?

$1 L C O_{2}, 1 L CO$

$2 L C O_{2}, 2 L CO$

$1 L C O_{2}, 2 L CO$

$2 L C O_{2}, 1 L CO$

$2 vol 2 CO + 1 vol O_{2} \to 2 vol 2 C O_{2}$
$1$ vol of $O_{2}$ reacts with $2$ vol of $CO$
$1 L$ of $O_{2}$ reacts with $2 L$ of $CO$
$CO$ left after reaction $= 3 - 2 = 1 L$
$1 L$ of $O_{2}$ produces $2 L$ of $C O_{2}$ .
Hence, after the reaction, $CO = 1 L, C O_{2} = 2 L$

Q. At NTP, 1L of O2​ reacts with 3L of carbon monoxide. What will be the volume of CO and CO2​ after the reaction?

1LCO2​,1LCO

2LCO2​,2LCO

1LCO2​,2LCO

2LCO2​,1LCO