Thank you for reporting, we will resolve it shortly
Q.
At $NTP$, $1\, L$ of $O_{2}$ reacts with $3 \,L$ of carbon monoxide. What will be the volume of $CO$ and $CO_{2}$ after the reaction?
Some Basic Concepts of Chemistry
Solution:
$\underset{\text{2 vol}}{2CO}+\underset{\text{1 vol}}{O_2} \to \underset{\text{2 vol}}{2CO_2}$
$1$ vol of $O_{2}$ reacts with $2$ vol of $CO$
$1\, L $ of $O_{2}$ reacts with $2\, L$ of $CO$
$ CO$ left after reaction $= 3 - 2 = 1\, L$
$ 1\, L$ of $O_2$ produces $2 \,L$ of $CO_2$.
Hence, after the reaction, $CO = 1\, L, CO_2 = 2\, L$