At low temperature, phenol reacts with Br2 in CS2 to form

Question

At low temperature, phenol reacts with Br2 in CS2 to form (A) m-bromophenol (B) o-and p-bromophenol (C) p-bromophenol (D) 2, 4, 6-tribromophenol

Tardigrade Admin · Accepted Answer

In presence of non-polar solvent (CS2) the ionisation of phenol is suppressed. The ring is slightly activated and hence, mono substitution occurs. On the other hand with Br2 water phenol gives 2, 4, 6-tribromo phenol.

Q. At low temperature, phenol reacts with $B r_{2}$ in $C S_{2}$ to form

m-bromophenol

o-and p-bromophenol

p-bromophenol

2, 4, 6-tribromophenol

In presence of non-polar solvent $(C S_{2})$ the ionisation of phenol is suppressed. The ring is slightly activated and hence, mono substitution occurs. On the other hand with $B r_{2}$ water phenol gives $2, 4, 6$ -tribromo phenol.

Q. At low temperature, phenol reacts with Br2​ in CS2​ to form