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  4. At low temperature, phenol reacts with Br2 in CS2 to form

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Q. At low temperature, phenol reacts with $ Br_{2} $ in $ CS_{2} $ to form

AMUAMU 2007

Solution:

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In presence of non-polar solvent $ (CS_{2}) $ the ionisation of phenol is suppressed. The ring is slightly activated and hence, mono substitution occurs. On the other hand with $Br_2$ water phenol gives $2, 4, 6$-tribromo phenol.
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