At constant temperature, the equilibrium constant (.Kp.) for the decomposition reaction N2O4(. textg.)leftharpoons2(NO)2(. textg.) is expressed by Kp=((. 4 x2 P .)/(. 1 - x2 .)) , where P = pressure, x = extent of decomposition. Which one of the following statements is true?

Question

At constant temperature, the equilibrium constant (.Kp.) for the decomposition reaction N2O4(. textg.)leftharpoons2(NO)2(. textg.) is expressed by Kp=((. 4 x2 P .)/(. 1 - x2 .)) , where P = pressure, x = extent of decomposition. Which one of the following statements is true? (A) Kp remains constant with change in P and x (B) Kp increases with decrease of x (C) Kp increases with increase of x (D) Kp increases with increase of P

Tardigrade Admin · Accepted Answer

Kp can be written as: textK textp = ([ textNO2]2/[ textN text2 textO4]) With change of pressure, x will change in such a way that Kp remains a constant.

Q. At constant temperature, the equilibrium constant $(K_{p})$ for the decomposition reaction $N_{2} O_{4} (g) ⇌ 2 (NO)_{2} (g)$ is expressed by $K_{p} = \frac{( 4 x ^{2} P )}{( 1 - x ^{2} )}$ , where P = pressure, x = extent of decomposition. Which one of the following statements is true?

$K_{p}$ remains constant with change in P and x

$K_{p}$ increases with decrease of x

$K_{p}$ increases with increase of x

$K_{p}$ increases with increase of P

$K_{p}$ can be written as:
$K_{p} = \frac{[ NO _{2} ] ^{2}}{[ N _{2} O _{4} ]}$
With change of pressure, x will change in such a way that $K_{p}$ remains a constant.

Q. At constant temperature, the equilibrium constant (Kp​) for the decomposition reaction N2​O4​(g)⇌2(NO)2​(g) is expressed by Kp​=(1−x2)(4x2P)​ , where P = pressure, x = extent of decomposition. Which one of the following statements is true?

Kp​ remains constant with change in P and x

Kp​ increases with decrease of x

Kp​ increases with increase of x

Kp​ increases with increase of P