At certain hill-station pure water boils at 99.725°C.If Kb for water is 0.513°C kg mol-1. The boiling point of 0.69 m solution of urea will be

Question

At certain hill-station pure water boils at 99.725°C.If Kb for water is 0.513°C kg mol-1. The boiling point of 0.69 m solution of urea will be (A) 100.079°C (B) 103°C (C) 100.359°C (D) unpredictable

Tardigrade Admin · Accepted Answer

Δ Tb = Kb × m = 0.513 × 0.69 = 0.3539° ∴ b.pt. of solution = 99.725° + 0.3539° C = 100.079°

Q. At certain hill-station pure water boils at 99.725 $^{\circ}$ C.If $K_{b}$ for water is 0.513 $^{\circ}$ C $k g m o l^{- 1}$ . The boiling point of 0.69 m solution of urea will be

100.079 $^{\circ}$ C

103 $^{\circ}$ C

100.359 $^{\circ}$ C

unpredictable

$Δ T_{b} = K_{b} \times m = 0.513 \times 0.69 = 0.353 9^{\circ}$
$∴$ b.pt. of solution = $99.72 5^{\circ} + 0.353 9^{\circ} C$
= $100.07 9^{\circ}$

Q. At certain hill-station pure water boils at 99.725∘C.If Kb​ for water is 0.513∘C kgmol−1. The boiling point of 0.69 m solution of urea will be

100.079∘C

103∘C

100.359∘C