Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. At certain hill-station pure water boils at 99.725$^\circ$C.If $K_b$ for water is 0.513$^\circ$C $kg mol^{-1}$. The boiling point of 0.69 m solution of urea will be

Solutions

Solution:

$\Delta \, T_b = K_b \times m = 0.513 \times 0.69 = 0.3539^{\circ} $
$\therefore $ b.pt. of solution = $99.725^{\circ} + 0.3539^{\circ} C$
= $100.079^{\circ}$