Question

At an angle of $30^{\circ }$ to the magnetic meridian, the apparent dip is $45^{\circ }$. Find the true dip:

• A. ${\tan }^{-1}\sqrt{3}$
• B. ${\tan }^{-1}\frac{1}{\sqrt{3}}$
• C. ${\tan }^{-1}\frac{2}{\sqrt{3}}$
• D. ${\tan }^{-1}\frac{\sqrt{3}}{2}$

Answer 1

Answer: (D)

$A\tan \delta =\tan {\delta }^{\prime }\cos \theta$
$=\tan 45^{\circ }\cos 30^{\circ }$
$\tan \delta =1\times \frac{\sqrt{3}}{2}$
$\delta ={\tan }^{-1}\left(\frac{\sqrt{3}}{2}\right)$