Question

At an angle of $30^{\circ}$ to the magnetic meridian, the apparent dip is $45^{\circ}$. Find the true dip:

• A. $\tan ^{-1} \sqrt{3}$
• B. $\tan ^{-1} \frac{1}{\sqrt{3}}$
• C. $\tan ^{-1} \frac{2}{\sqrt{3}}$
• D. $\tan ^{-1} \frac{\sqrt{3}}{2}$

Answer 1

Answer: (D)

$A \tan \delta=\tan \delta^{\prime} \cos \theta$
$=\tan 45^{\circ} \cos 30^{\circ}$
$\tan \delta=1 \times \frac{\sqrt{3}}{2}$
$\delta=\tan ^{-1}\left(\frac{\sqrt{3}}{2}\right)$