At a particular locus, frequency of 'A' allele is 0.6 and that of ' a ' is 0.4. What would be the frequency of heterozygotes in a randomly mating population of equilibrium?

Question

At a particular locus, frequency of 'A' allele is 0.6 and that of ' a ' is 0.4. What would be the frequency of heterozygotes in a randomly mating population of equilibrium? (A) 0.16 (B) 0.36 (C) 0.48 (D) 0.24

Tardigrade Admin · Accepted Answer

According to Hardy-Weinberg equation, P2+2 P Q+Q2=1 Where, P= Dominant allele frequency Q= Recessive allele frequency P2= Homozygous dominant genotype 2 P Q= Heterozygous genotype Q2 = Homozygous recessive genotype Here, P=0.6 and Q=0.4 Therefore, 2 P Q=2 × 0.6 × 0.4 = 0.48

Q. At a particular locus, frequency of 'A' allele is 0.6 and that of ' a ' is 0.4. What would be the frequency of heterozygotes in a randomly mating population of equilibrium?

0.16

0.36

0.48

0.24

According to Hardy-Weinberg equation, P2+2PQ+Q2=1 Where, P= Dominant allele frequency Q= Recessive allele frequency P2= Homozygous dominant genotype 2PQ= Heterozygous genotype Q2 = Homozygous recessive genotype Here, P=0.6 and Q=0.4 Therefore, 2PQ=2×0.6×0.4 =0.48

Q. At a particular locus, frequency of 'A' allele is $0.6$ and that of ' $a$ ' is $0.4$ . What would be the frequency of heterozygotes in a randomly mating population of equilibrium?