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Q. At a particular locus, frequency of 'A' allele is $0.6$ and that of ' $a$ ' is $0.4$. What would be the frequency of heterozygotes in a randomly mating population of equilibrium?

AIIMSAIIMS 2014

Solution:

According to Hardy-Weinberg equation,
$P^{2}+2 P Q+Q^{2}=1$
Where, $P=$ Dominant allele frequency
$Q=$ Recessive allele frequency
$P^{2}=$ Homozygous dominant genotype
$2 P Q=$ Heterozygous genotype
$Q^{2}$ = Homozygous recessive genotype
Here, $P=0.6$ and $Q=0.4$
Therefore, $2 P Q=2 \times 0.6 \times 0.4$
$= 0.48$