At a given temperature the equilibrium constant for the reaction of: PCl5 PCl3 + Cl2is 2.4 × 10−3 . At the same temperature, the equilibrium constant for the reaction PCl3(g) + Cl2(g) PCl5(g) is :

Question

At a given temperature the equilibrium constant for the reaction of: PCl5 <=> PCl3 + Cl2is 2.4 × 10−3 . At the same temperature, the equilibrium constant for the reaction PCl3(g) + Cl2(g) <=> PCl5(g) is : (A) 2.4 × 10−3 (B) -2.4 × 10−3 (C) 4.2 × 102 (D) 4.8 × 10−2

Tardigrade Admin · Accepted Answer

Given, PCl 5 leftharpoons PCl 3+ Cl 2 k=2.4 × 10-3 PCl 3+ Cl 2 leftharpoons PCl 5 k'= ? ∴ k'=(1/k)=(1/2.4 × 10-3)=4.2 × 102

Q. At a given temperature the equilibrium constant for the reaction of :
$PC l_{5} PC l_{3} + C l_{2}$ is $2.4 \times 1 0^{- 3}$ . At the same temperature, the equilibrium constant for the reaction
$PC l_{3} (g) + C l_{2} (g) PC l_{5} (g)$ is :

$2.4 \times 1 0^{- 3}$

$- 2.4 \times 1 0^{- 3}$

$4.2 \times 1 0^{2}$

$4.8 \times 1 0^{- 2}$

Given, $PC l_{5} ⇌ PC l_{3} + C l_{2} k = 2.4 \times 1 0^{- 3}$

$PC l_{3} + C l_{2} ⇌ PC l_{5} k^{'} =$ ?

$∴ k^{'} = \frac{1}{k} = \frac{1}{2.4 \times 1 0 ^{- 3}} = 4.2 \times 1 0^{2}$

Q. At a given temperature the equilibrium constant for the reaction of : PCl5​​PCl3​+Cl2​is 2.4×10−3 . At the same temperature, the equilibrium constant for the reaction PCl3​(g)+Cl2​(g)​PCl5​(g) is :

2.4×10−3

−2.4×10−3

4.2×102

4.8×10−2