1. Tardigrade
  2. Question
  3. Chemistry
  4. At a given temperature the equilibrium constant for the reaction of: PCl5 <=> PCl3 + Cl2is 2.4 × 10−3 . At the same temperature, the equilibrium constant for the reaction PCl3(g) + Cl2(g) <=> PCl5(g) is :

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Q. At a given temperature the equilibrium constant for the reaction of :
$PCl_5 \ce{<=> } PCl_3 + Cl_2$is $ 2.4 × 10^{−3} $ . At the same temperature, the equilibrium constant for the reaction
$ PCl_3(g) + Cl_2(g) \ce{<=>} PCl_5(g)$ is :

UPSEEUPSEE 2005

Solution:

Given, $PCl _{5} \rightleftharpoons PCl _{3}+ Cl _{2} \quad k=2.4 \times 10^{-3}$

$PCl _{3}+ Cl _{2} \rightleftharpoons PCl _{5} \,\,\, k'=$ ?

$\therefore \,k'=\frac{1}{k}=\frac{1}{2.4 \times 10^{-3}}=4.2 \times 10^{2}$