At a certain temperature, equilibrium constant (Kc) is 16 for the reaction. SO 2(g)+ NO 2(g) leftharpoons SO 3(g)+ NO (g) If we take one mole each of all the four gases in a one litre container, what would be the equilibrium concentrations of NO and NO 2 ?

Question

At a certain temperature, equilibrium constant (Kc) is 16 for the reaction. SO 2(g)+ NO 2(g) leftharpoons SO 3(g)+ NO (g) If we take one mole each of all the four gases in a one litre container, what would be the equilibrium concentrations of NO and NO 2 ? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/5dc3ee530133766b9e418fc45271d09a-.png" /> QC =1< Kc i.e. reaction proceed in forward direction to attain equilibrium. 16=((x/1-x))2 ⇒ x=0.80 [N O]=0.80 M, [N O2]=0.20 M

Q. At a certain temperature, equilibrium constant $(K_{c})$ is $16$ for the reaction.
$S O_{2} (g) + N O_{2} (g) ⇌ S O_{3} (g) + NO (g)$
If we take one mole each of all the four gases in a one litre container, what would be the equilibrium concentrations of $NO$ and $N O_{2}$ ?

$QC = 1 < K_{c}$
i.e. reaction proceed in forward direction to attain equilibrium.
$16 = (\frac{x}{1 - x})^{2}$
$\Rightarrow x = 0.80$
$[NO] = 0.80 M,$
$[N O_{2}] = 0.20 M$

Q. At a certain temperature, equilibrium constant (Kc​) is 16 for the reaction. SO2​(g)+NO2​(g)⇌SO3​(g)+NO(g) If we take one mole each of all the four gases in a one litre container, what would be the equilibrium concentrations of NO and NO2​ ?

QC=1<Kc​ i.e. reaction proceed in forward direction to attain equilibrium. 16=(1−xx​)2 ⇒x=0.80 [NO]=0.80M, [NO2​]=0.20M

Q. At a certain temperature, equilibrium constant $(K_{c})$ is $16$ for the reaction.
$S O_{2} (g) + N O_{2} (g) ⇌ S O_{3} (g) + NO (g)$
If we take one mole each of all the four gases in a one litre container, what would be the equilibrium concentrations of $NO$ and $N O_{2}$ ?

$QC = 1 < K_{c}$
i.e. reaction proceed in forward direction to attain equilibrium.
$16 = (\frac{x}{1 - x})^{2}$
$\Rightarrow x = 0.80$
$[NO] = 0.80 M,$
$[N O_{2}] = 0.20 M$