At a certain place the angle of dip is 30° and the horizontal component of earth's magnetic field is 0.50 oersted. The earth's total magnetic field is

Question

At a certain place the angle of dip is 30° and the horizontal component of earth's magnetic field is 0.50 oersted. The earth's total magnetic field is (A) √3 (B) 1 (C) (1/√3) (D) (1/2)

Tardigrade Admin · Accepted Answer

BH=B cos φ, ∴ B=(BH/ cos φ)=(0.5/ cos 30°) =(0.5/√3 / 2)=(1/√3)

Q. At a certain place the angle of dip is $3 0^{\circ}$ and the horizontal component of earth's magnetic field is $0.50$ oersted. The earth's total magnetic field is

$3$

$1$

$\frac{1}{3}$

$\frac{1}{2}$

$B_{H} = B cos ϕ,$
$∴ B = \frac{B _{H}}{c o s ϕ} = \frac{0.5}{c o s 3 0 ^{\circ}}$
$= \frac{0.5}{3 /2} = \frac{1}{3}$

Q. At a certain place the angle of dip is 30∘ and the horizontal component of earth's magnetic field is 0.50 oersted. The earth's total magnetic field is

3​

1

3​1​

21​

BH​=Bcosϕ, ∴B=cosϕBH​​=cos30∘0.5​ =3​/20.5​=3​1​

Q. At a certain place the angle of dip is $3 0^{\circ}$ and the horizontal component of earth's magnetic field is $0.50$ oersted. The earth's total magnetic field is

$3$

$1$

$\frac{1}{3}$

$\frac{1}{2}$

$B_{H} = B cos ϕ,$
$∴ B = \frac{B _{H}}{c o s ϕ} = \frac{0.5}{c o s 3 0 ^{\circ}}$
$= \frac{0.5}{3 /2} = \frac{1}{3}$