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Q. At a certain place the angle of dip is $30^{\circ}$ and the horizontal component of earth's magnetic field is $0.50$ oersted. The earth's total magnetic field is

Magnetism and Matter

Solution:

$B_{H}=B \cos \phi,$
$\therefore B=\frac{B_{H}}{\cos \phi}=\frac{0.5}{\cos 30^{\circ}}$
$=\frac{0.5}{\sqrt{3} / 2}=\frac{1}{\sqrt{3}}$