At a certain place the angle of dip is 30° and the horizontal component of earth's magnetic field is 0.5 G. The earth's total magnetic field (in G ), at that certain place, is :

Question

At a certain place the angle of dip is 30° and the horizontal component of earth's magnetic field is 0.5 G. The earth's total magnetic field (in G ), at that certain place, is : (A) (1/√3) (B) (1/2) (C) √3 (D) 1

Tardigrade Admin · Accepted Answer

B H = B cos θ ∴ B =( B H / cos θ)=(0.5 G / cos 30°) ⇒ ( G /√3)

Q. At a certain place the angle of dip is $3 0^{\circ}$ and the horizontal component of earth's magnetic field is $0.5 G$ . The earth's total magnetic field (in $G$ ), at that certain place, is :

$\frac{1}{3}$

$\frac{1}{2}$

$3$

$1$

$B_{H} = B cos θ$
$∴ B = \frac{B _{H}}{c o s θ} = \frac{0.5 G}{c o s 3 0 ^{\circ}} \Rightarrow \frac{G}{3}$

Q. At a certain place the angle of dip is 30∘ and the horizontal component of earth's magnetic field is 0.5G. The earth's total magnetic field (in G ), at that certain place, is :

3​1​

21​

3​

1

BH​=Bcosθ ∴B=cosθBH​​=cos30∘0.5G​⇒3​G​

Q. At a certain place the angle of dip is $3 0^{\circ}$ and the horizontal component of earth's magnetic field is $0.5 G$ . The earth's total magnetic field (in $G$ ), at that certain place, is :

$\frac{1}{3}$

$\frac{1}{2}$

$3$

$1$

$B_{H} = B cos θ$
$∴ B = \frac{B _{H}}{c o s θ} = \frac{0.5 G}{c o s 3 0 ^{\circ}} \Rightarrow \frac{G}{3}$