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  4. At a certain place the angle of dip is 30° and the horizontal component of earth's magnetic field is 0.5 G. The earth's total magnetic field (in G ), at that certain place, is :

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Q. At a certain place the angle of dip is $30^{\circ}$ and the horizontal component of earth's magnetic field is $0.5 \,G$. The earth's total magnetic field (in $G$ ), at that certain place, is :

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Solution:

$B _{ H }= B \cos \theta$
$\therefore B =\frac{ B _{ H }}{\cos \theta}=\frac{0.5 G }{\cos 30^{\circ}} \Rightarrow \frac{ G }{\sqrt{3}}$