At 88° C, benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. Assuming that benzene and toluene form an ideal solution, calculate the mole fraction of benzene in a mixture if the total pressure is 500 torr at 88° C.

Question

At 88° C, benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. Assuming that benzene and toluene form an ideal solution, calculate the mole fraction of benzene in a mixture if the total pressure is 500 torr at 88° C. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

p T = p A 0 x A + p B 0 x B = p A 0 x A + p B 0(1-x A ) ∴ 500=900 x A +360(1-x A ) ∴ 500=900 x A +360-360 x A ∴ 140=540 x A Therefore, x A =0.26

Q. At $8 8^{\circ} C$ , benzene has a vapour pressure of $900$ torr and toluene has a vapour pressure of $360$ torr. Assuming that benzene and toluene form an ideal solution, calculate the mole fraction of benzene in a mixture if the total pressure is $500$ torr at $8 8^{\circ} C$ .

$p_{T} = p_{A}^{0} x_{A} + p_{B}^{0} x_{B} = p_{A}^{0} x_{A} + p_{B}^{0} (1 - x_{A})$
$∴ 500 = 900 x_{A} + 360 (1 - x_{A})$
$∴ 500 = 900 x_{A} + 360 - 360 x_{A}$
$∴ 140 = 540 x_{A}$
Therefore, $x_{A} = 0.26$

Q. At 88∘C, benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. Assuming that benzene and toluene form an ideal solution, calculate the mole fraction of benzene in a mixture if the total pressure is 500 torr at 88∘C.

pT​=pA0​xA​+pB0​xB​=pA0​xA​+pB0​(1−xA​) ∴500=900xA​+360(1−xA​) ∴500=900xA​+360−360xA​ ∴140=540xA​ Therefore, xA​=0.26

Q. At $8 8^{\circ} C$ , benzene has a vapour pressure of $900$ torr and toluene has a vapour pressure of $360$ torr. Assuming that benzene and toluene form an ideal solution, calculate the mole fraction of benzene in a mixture if the total pressure is $500$ torr at $8 8^{\circ} C$ .

$p_{T} = p_{A}^{0} x_{A} + p_{B}^{0} x_{B} = p_{A}^{0} x_{A} + p_{B}^{0} (1 - x_{A})$
$∴ 500 = 900 x_{A} + 360 (1 - x_{A})$
$∴ 500 = 900 x_{A} + 360 - 360 x_{A}$
$∴ 140 = 540 x_{A}$
Therefore, $x_{A} = 0.26$