At 300 K, the ratio of the average molecular kinetic energy of textU textF text6 to that of textH2 is:

Question

At 300 K, the ratio of the average molecular kinetic energy of textU textF text6 to that of textH2 is: (A) 2: 7 (B) 7: 2 (C) 6: 2 (D) 1: 1

Tardigrade Admin · Accepted Answer

Average molecular kinetic energy =(3/2)kT Given, T = 300 K for both UF2 and H2. ∴ Average molecular kinetic energy does not depend on molecular mass of substance. Average molecular kinetic energy of H2 =(3/2)K× 300 ....(i) Average molecular kinetic energy of UF2 =(3/2)k× 300 ....(ii) Dividing Eq. ....(i) by Eq. (ii) we get 1: 1

Q. At $300 K$ , the ratio of the average molecular kinetic energy of $U F_{6}$ to that of $H_{2}$ is:

2 : 7

7 : 2

6 : 2

1 : 1

Q. At 300K, the ratio of the average molecular kinetic energy of UF6​ to that of H2​ is:

2 : 7

7 : 2

6 : 2

1 : 1

Q. At $300 K$ , the ratio of the average molecular kinetic energy of $U F_{6}$ to that of $H_{2}$ is: