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Q.
At $300\, K$, the ratio of the average molecular kinetic energy of $ \text{U}{{\text{F}}_{\text{6}}} $ to that of $ {{\text{H}}_{2}} $ is:
Bihar CECEBihar CECE 2001States of Matter
Solution:
Average molecular kinetic energy $ =\frac{3}{2}kT $
Given, T = 300 \,K for both $ U{{F}_{2}} $ and $ {{H}_{2}}. $
$ \therefore $ Average molecular kinetic energy does not depend on molecular mass of substance. Average molecular kinetic energy of $ {{H}_{2}} $
$ =\frac{3}{2}K\times 300 $ ....(i)
Average molecular kinetic energy of $ U{{F}_{2}} $
$ =\frac{3}{2}k\times 300 $....(ii)
Dividing Eq. ....(i) by Eq. (ii) we get
1 : 1