At 298 K, the enthalpy of fusion of a solid (X) is 2.8 kJ mol -1 and the enthalpy of vaporisation of the liquid (X) is 98.2 kJ mol -1. The enthalpy of sublimation of the substance (X) in kJ mol -1 is (in nearest integer)

Question

At 298 K, the enthalpy of fusion of a solid (X) is 2.8 kJ mol -1 and the enthalpy of vaporisation of the liquid (X) is 98.2 kJ mol -1. The enthalpy of sublimation of the substance (X) in kJ mol -1 is (in nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ H text sub =Δ H text fivs. +Δ H text vap. =2.8+98.2 =101 kJ / mol

Q. At $298 K$ , the enthalpy of fusion of a solid $(X)$ is $2.8 k J m o l^{- 1}$ and the enthalpy of vaporisation of the liquid $(X)$ is $98.2 k J m o l^{- 1}$ . The enthalpy of sublimation of the substance $(X)$ in $k J m o l^{- 1}$ is________ (in nearest integer)

$Δ H_{sub} = Δ H_{fivs.} + Δ H_{vap.}$
$= 2.8 + 98.2$
$= 101 k J / m o l$

Q. At 298K, the enthalpy of fusion of a solid (X) is 2.8kJmol−1 and the enthalpy of vaporisation of the liquid (X) is 98.2kJmol−1. The enthalpy of sublimation of the substance (X) in kJmol−1 is________ (in nearest integer)

ΔHsub ​=ΔHfivs. ​+ΔHvap. ​ =2.8+98.2 =101kJ/mol

Q. At $298 K$ , the enthalpy of fusion of a solid $(X)$ is $2.8 k J m o l^{- 1}$ and the enthalpy of vaporisation of the liquid $(X)$ is $98.2 k J m o l^{- 1}$ . The enthalpy of sublimation of the substance $(X)$ in $k J m o l^{- 1}$ is________ (in nearest integer)

$Δ H_{sub} = Δ H_{fivs.} + Δ H_{vap.}$
$= 2.8 + 98.2$
$= 101 k J / m o l$